9r^2+3r+4=8r^2-r

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Solution for 9r^2+3r+4=8r^2-r equation:



9r^2+3r+4=8r^2-r
We move all terms to the left:
9r^2+3r+4-(8r^2-r)=0
We get rid of parentheses
9r^2-8r^2+3r+r+4=0
We add all the numbers together, and all the variables
r^2+4r+4=0
a = 1; b = 4; c = +4;
Δ = b2-4ac
Δ = 42-4·1·4
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$r=\frac{-b}{2a}=\frac{-4}{2}=-2$

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